7(x^2-35)=0

Solution for 7(x^2-35)=0 equation:

7(x^2-35)=0

We multiply parentheses

7x^2-245=0

a = 7; b = 0; c = -245;
Δ = b2-4ac
Δ = 02-4·7·(-245)
Δ = 6860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6860}=\sqrt{196*35}=\sqrt{196}*\sqrt{35}=14\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{35}}{2*7}=\frac{0-14\sqrt{35}}{14}
=-\frac{14\sqrt{35}}{14}
=-\sqrt{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{35}}{2*7}=\frac{0+14\sqrt{35}}{14}
=\frac{14\sqrt{35}}{14}
=\sqrt{35}
$